y=5x/1-6x^2. find dy/dx

y = \frac{5 x}{1 - 6 x^{2}} W e s h a l l u s e q u o t i e n t r u l e o f d i f f e r e n t i a t i o n h e r e \frac{d y}{d x} = \frac{(1 - 6 x^{2}) \frac{d 5 x}{d x} - 5 x \frac{d (1 - 6 x^{2})}{d x}}{{(1 - 6 x^{2})}^{2}} = \frac{(1 - 6 x^{2}) \times 5 \frac{d x}{d x} - 5 x \{\frac{d 1}{d x} - 6 \frac{d x^{2}}{d x}\}}{{(1 - 6 x^{2})}^{2}} = \frac{(1 - 6 x^{2}) \times 5 - 5 x \{- 12 x\}}{{(1 - 6 x^{2})}^{2}} = \frac{5 - 30 x^{2} + 60 x^{2}}{{(1 - 6 x^{2})}^{2}} = \frac{30 x^{2} + 5}{{(1 - 6 x^{2})}^{2}}

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