​In the fig AM_I_BC, AN bisects <A. If <ABC=700 and <ACB=200. FIND THE VALUE <MAN

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rd main solution hai iska..
 
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Firstly, In tri. ABC, Angle BAC = 90[As 2 angles are given]Now, Angle NAB = 45 [AN bisects Angle BAC].Now, In triangle ANB, Angle ABN = 70 , Angle BAN = 45 , SO, Angle BNA = 180 - 70 - 45 = 65.Finally, In triangle AMN, Angle M = 90 , Angle N = 65 , so, Angle MAN = 180 - 90 - 65 = 25.so, Angle MAN = 45
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So, Angle MAN = 25[Replace 45 with 25 at end]
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What are you looking for?