Rs Aggrawal 2020 2021 Solutions for Class 6 Maths Chapter 4 Integers are provided here with simple step-by-step explanations. These solutions for Integers are extremely popular among Class 6 students for Maths Integers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggrawal 2020 2021 Book of Class 6 Maths Chapter 4 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggrawal 2020 2021 Solutions. All Rs Aggrawal 2020 2021 Solutions for class Class 6 Maths are prepared by experts and are 100% accurate.

#### Page No 63:

(i) A decrease of 8
(ii) A gain of Rs 7
(iii) Losing a weight of 5 kg
(iv) 10 km below the sea level
(v) 5oC above the freezing point
(vi) A withdrawal of Rs 100
(vii) Spending Rs 500
(viii) Going 6 m to the west
(ix) The opposite of 24 is -24.
(x) The opposite of -34 is 34.

(i) +Rs 600
(ii) -Rs 800
(iii) -7oC
(iv) -9
(v) +2 km
(vi) -3 km
(vii) + Rs 200
(viii) -Rs 300

#### Page No 64:

(i) -5 (ii) -2 (iii) 0 (iv) 7  #### Page No 64:

(i)0, -2
0 > -2
This is because zero is greater than every negative integer.

(ii) -3, -5
-3 > -5
Since 3 is smaller than 5, -3 is greater than -5.

(iii) -5, 2
2 > -5
This is because every positive integer is greater than every negative integer.

(iv) -16, 8
8 > -16
This is because every positive integer is greater than every negative integer.
v) -365, -913
-365 > -913
Since 365 is smaller than 913,  -365 is greater than -913.
vi) -888, 8
8 > -888
This is because every positive integer is greater than every negative integer.

#### Page No 64:

i) -7 < 6
This is because every positive integer is greater than every negative integer.
ii) -1 < 0
This is because zero is greater than every negative integer.
iii) -27 < -13
Since 27 is greater than 13, -27 is smaller than -13.
iv) -26 < 17
This is because every positive integer is greater than every negative integer.
v) -603 < -317
Since 603 is greater than 317, -603 is smaller than -317.
vi) -777 < 7
This is because every positive integer is greater than every negative integer.

#### Page No 64:

i) 1, 2, 3, 4, 5

ii) -4, -3, -2, -1

iii) -2, -1, 0, 1, 2

iv) -6

#### Page No 64:

i) 0 < 7
This is because 0 is less than any positive integer.
ii) 0 > -3
This is because 0 is greater than any negative integer.
iii) -5 < -2
Since 5 is greater than 2, -5 is smaller than -2.
iv) -15 < 13
This is because every positive integer is greater than every negative integer.
v) -231 < -132
Since 231 is greater than 132, -231 is smaller than -132.
vi) -6 < 6
This is because every positive integer is greater than every negative integer.

#### Page No 64:

i) -7 < -2 < 0 < 5 < 8
ii) -100 < -23 < -6 < -1 < 0 < 12
iii) -501 < -363 < -17 < 15 < 165
iv) -106 < -81 < -16 < -2 < 0 < 16 < 21

#### Page No 64:

i) 36 > 7 > 0 > -3 > -9 > -132
ii) 51 > 0 > -2 > -8 > -53
iii) 36 > 0 > -5 > -71 > -81
iv) 413 > 102 > -7 > -365 > -515

#### Page No 64:

i) 4 more than 6
We want an integer that is 4 more than 6. So, we will start from 6 and proceed 4 steps to the right to obtain 10. ii) 5 more than -6
We want an integer that is 5 more than -6. So, we will start from -6 and proceed 5 steps to the right to obtain -1. iii) 6 less than 2
We want an integer that is 6 less than 2. So, we will start from 2 and proceed 6 steps to the left to obtain -4. iv) 2 less than -3
We want an integer that is 2 less than -3. So, we will start from -3 and proceed 2 steps to the left to obtain -5 #### Page No 64:

i) False
This is because 0 is greater than every negative integer.

ii) False
0 is an integer as we know that every whole number is an integer and 0 is a whole number.

iii) True
0 is an integer that is neither positive nor negative. So, the opposite of zero is zero.

iv) False
Since 10 is greater than 6, -10 is smaller than -6.

v) True
This is because an absolute value is a positive number. For example, -2 is an integer, but its absolute value is 2 and it is greater than -2.

vi) True
This is because all negative integers are to the left of 0.

vii) True
This is because natural numbers are positive and every positive integer is greater than every negative integer.

viii) False
This is because the successor of -187 is equal to -186 (-186 + 1). In succession, we move from the left to the right along a number line.

ix) False
This is because the predecessor of -215 is -216 (-216 - 1). To find the predecessor, we move from the right to the left along a number line.

#### Page No 64:

i) The value of |-9| is 9
ii) The value of |-36| is 36
iii) The value of |0| is 0
iv) The value of |15| is 15
v) The value of |-3| is 3
$\therefore$ -|-3| = -3

vi) 7 + |-3|
= 7 + 3          (The value of |-3| is 3)
= 10

vii) |7 - 4|
= |3|
= 3                 (The value of |3| is 3)

viii) 8 - |-7|
= 8 - 7           (The value of |-7| is 7)
= 1

#### Page No 64:

i) Every negative integer that is to the right of -7 is greater than -7.
So, five negative integers that are greater than -7 are -6, -5, -4, -3, -2 and -1.

ii) Every negative integer that is to the left of -20 is less than -20.
So, five negative integers that are less than -20 are -21, -22, -23, -24 and -25.

#### Page No 68:

i) On the number line, we start from 0 and move 9 steps to the right to reach a point A. Now, starting from A, we move 6 steps to the left to reach point B. B represents the integer 3.
$\therefore$ 9 + (−6) = 3

(ii) On the number line, we start from 0 and move 3 steps to the left to reach point A. Now, starting from A, we move 7 steps to the right to reach point B.
B represents the integer 4.
$\therefore$ (3) + 7 = 4 (iii) On the number line, we start from 0 and move 8 steps to the right to reach point A. Now, starting from A, we move 8 steps to the left to reach point B.
B represents the integer 0.

$\therefore$ 8 + (8) = 0 (iv) On the number line, we start from 0 and move 1 step to the left to reach point A. Now, starting from A, we move 3 steps to the left to reach point B.
B represents the integer 4.

$\therefore$ (−1) + (3) = −4 (v) On the number line, we start from 0 and move 4 steps to the left to reach point A. Now, starting from A, we move 7 steps to the left to reach point B.
B represents the integer −11.

$\therefore$ (−4) + (−7) = −11 (vi) On the number line, we start from 0 and move 2 steps to the left to reach point A. Now, starting from A, we move 8 steps to the left to reach point B.
B represents the integer −10.

$\therefore$ (−2) + (−8) = −10 (vii) On the number line, we start from 0 and move 3 steps to the right to reach point A. Now, starting from A, we move 2 steps to the left to reach point B. Again, starting from B, we move 4 steps to the left to reach point C.
C represents the integer −3.

$\therefore$ 3 + (−2) + (−4) = −3 (viii) On the number line, we start from 0 and move 1 step to the left to reach point A. Now, starting from A, we move 2 steps to the left to reach point B. Again, starting from B, we move 3 steps to the left to reach point C.
C represents the integer −6.

$\therefore$ (−1) + (−2) + (−3) = −6 (ix) On the number line, we start from 0 and move 5 steps to the right to reach point A. Now, starting from A, we move 2 steps to the left to reach point B. Again, starting from B, we move 6 steps to the left to reach point C.
C represents the integer −3.

$\therefore$ 5 + (−2) + (−6) = −3 (i)
(−3) + (−9)
= −3 − 9
= −12

(ii)
(−7) + (−8)
= −7 − 8
= −15

(iii)
(−9) + 16
= −9 + 16
= 7

(iv)
(−13) + 25
= −13 + 25
= 12

(v)
8 + (−17)
= 8 − 17
= −9

(v)
2 + (−12)
= 2 − 12
= −10

#### Page No 68:

(i)

365
365  87 365  87 -365 and -87 are both negative integers. So, we add 365 and 87, and put the negative sign before the sum.

(ii)

-687 and -73 are both negative integers. So, we add 365 and 87, and put the negative sign before the sum.

(iii)

-1065 and -987 are both negative integers. So, we add 1065 and 987, and put the negative sign before the sum.

(iv)
$\begin{array}{l}-\text{3596}\\ \frac{-\text{1089}}{-4685}\end{array}$
-3596 and -1089 are both negative integers. So, we add 3596 and 1089, and put the negative sign before the sum.

#### Page No 68:

i)

ii)

(iii)

Since we are adding a negative number with a positive number,
we shall subtract the smaller number, i.e. -103, from the greater number, i.e. 312
312 - 103 = 209
Since the greater number is positive, the sign of the result will be positive.
So, the answer will be 209

Since we are adding a negative number with a positive number,
we shall subtract the smaller number, i.e. 289, from the greater number, i.e. 493.
493 - 289 = 204
Since the greater number is negative, the sign of the result will be negative.
So, the answer will be -204

#### Page No 68:

(viii) −18, + 25 and −37
25 + (−18) + (−37)
= 25 – (18 + 37)
= 25 – 55
= –30

(ix) −312, 39 and 192
39 + 192 + (−312)
= 39 + 192 - 312
= 231 −312
= −81
(x) −51, −203, 36 and −28
36 + (−51) + (−203) + (−28)
= 36 − (51 + 203 + 28)
= 36 – 282
= −246

#### Page No 68:

(i) −57 + 57 = 0
So, the additive inverse of −57 is 57
.

(ii) 183 − 183 = 0
So, the additive inverse of 183 is −183
.

(iii) 0 + 0 = 0
So, the additive inverse of 0 is 0.

(iv) −1001 + 1001 = 0
So, the additive inverse of​ −1001 is 1001
.

(v) 2054 − 2054 = 0
So, the additive inverse of​ 2054 is −2054

#### Page No 68:

(i) The successor of 201:
201 + 1 = 202
(ii) The successor of 70:
70 + 1 = 71
(iii) The successor of −5:

5 + 1 = −4
(iv) The successor of
−99:
99 + 1 = −98
(v) The successor of −500:
500 + 1 = 499

#### Page No 68:

(i) The predecessor of 120:
120
− 1 = 119
(ii) The predecessor of 79:
79
− 1 = 78
(iii) The predecessor of −8:

−8 − 1 = −9
(iv) The predecessor of
−141:
−141 − 1 = −142
​(v) The predecessor of −300:
−300 − 1 = 301

#### Page No 69:

(i) (−7) + (−9) + 12 + (−16)
= 12 − (7 + 9 + 16)
= 12 − 32
= −20

(ii)  37 + (−23) + (−65) + 9 + (−12)
= 37 + 9 − (23 + 65 + 12)
= 46-100
= −54

​(iii) (−145) + 79 + (−265) + (−41) + 2
= 79 +2 − ( 145 + 265 + 41)
= 81 − 451
= −370

(iv) 1056 + (−798) + (−38) + 44 + (−1)
= 1056 + 44 − (798 + 38 + 1)
= 1100 − 837
= −263

#### Page No 69:

Let the distance covered in the direction of north be positive and that in the direction of south be negative.

Distance travelled to the north of Patna = 60 km
Distance travelled to the south of Patna = -90 km
Total distance travelled by the car = 60 + (​-90)
= -30 km
The car was 30 km south of Patna.

#### Page No 69:

Total cost price  = Price of pencils + Price of pens
= 30 + 90 + 25
= Rs 145

Total amount sold = Price of pen + Price of pencils
= 20 + 70
= 90
Selling price - costing price = 90 $-$ 145
= $-$55
The negative sign implies loss.
Hence, his net loss was Rs 55.

#### Page No 69:

(i) True
For example: - 2 + (-1) = -3

(ii) False
It can be negative or positive.
For example: -2 + 3 = 1 gives a positive integer, but -5 + 2 = -3 gives a negative integer.

(iii) True
For example: 100 + (-100) = 0

(iv) False
For example: (-5) + 2 + 3 = 0

(v) False
|-5| = 5  and | -3 | = 3, 5 > 3

(vi) False
|8 − 5| = 3
|8| + |−5| = 8 + 5
= 13

$\therefore$ |8 − 5|$\ne$|8| + |−5|

#### Page No 69:

(i) a + 6 = 0
=> a = 0 − 6
=> a = − 6

(ii) 5 + a = 0
=> a = 0 − 5

(iii) a + (−4) = 0
=> a = 0 − (−4)
=> a = 4

(iv) −8 + a = 0
=> a = 0 + 8
=> a = 8

#### Page No 70:

(i) −34 − 18
= −52

(ii) 25 − (−15)
= 25 + 15
= 40
(iii) −28 from −43
= −43 − (−28)
= −43 + 28
​= −15

(iv) 68 from −37
= −37 − 68
= −105
​(v)  219 from 0
=  0 − 219
= −219

(vi) −92 from 0
= 0 − (−92)
= 0 + 92
= 92

(vii) −135 from −250
= −250 − (−135)
​= −250 + 135
= −115

(viii) −2768 from −287
= −287 − (−2768)
​= 2768 −​ 287
= 2481

(ix) 6240 from −271
= −271 − (6240)
= −271 − 6240
= −6511

(x) −3012 from 6250
= 6250 − (−3012)
= 6250 + 3012
​= 9262

#### Page No 70:

Sum of −1050 and 813:
−1050 + 813

−237
Subtracting the sum of −1050 and 813 from −23:
−23 − (−237)
= −23 +237
= 214

#### Page No 70:

Sum of 138 and −250:
138 + (
−250)
= 138 − 250
= −112
Sum of 136 and −272:
= 136 + (−272)
= 136 − 272

= −136
Subtracting the sum of −250 and 138 from the sum of 136 and −272:
−136 − (
−112​)
= −136 + 112​
= 24

#### Page No 70:

​33 + (−47)
= 33 − 47
= −14

Subtracting −84 from −14:
−14 − (−84)
= −14 + 84
= 70

#### Page No 70:

Difference of −8 and −68:
−8 − (−68)
​= −8 + 68
= 60

−36 + 60
= 24

#### Page No 70:

(i) [37 − (−8)] + [11 − (−30)]
= (37 + 8) + (11 + 30)
= 45 + 41
= 86

(ii) [−13 − (−17) + [−22 − (−40)]
=  (
−13 +17) + (-22 + 40)
= 4 + 18
= 22

#### Page No 70:

No, they are not equal.

34 − (−72)
= 34 +
72
​= 106

(−72) − 34
= −72
34
106

Since 106 is not equal to −106, the two expressions are not equal.

#### Page No 70:

Let the other integer be x.
According to question, we have:
x + 170 =  −13
=> x = −13 − 170
=>  x = −183
Thus, the other integer is −183
.

#### Page No 70:

Let the other integer be x.
According to question, we have:
x + (−47) = 65
=> x − 47 = 65
=>  x = 65 + 47
=> x = 112
Thus, the other integer is 112.

#### Page No 70:

(i) True
An integer added to an integer gives an integer.

(ii) True
An integer subtracted from an integer gives an integer.

iii) False
−8 − (−7)
= −8 + 7
= −1
Since 14 is greater than 1, −1 is greater than −14.

iv) True
−5 − 2 = −7
Since 8 is greater than 7, −7 is greater than −8.
− 7 > −8

​v) False
L.H.S.
(−7) − 3 = −10
R.H.S.
(−3) − (−7)
= (−3) + 7
= 4
$\therefore$ L.H.S. $\ne$ R.H.S.

#### Page No 71:

Let us consider the height above the sea level as positive and that below the sea level as negative.
$\therefore$ Height of point A from sea level = 5700 m
Depth of point B from sea level = -39600 m
Vertical distance between A and B = Distance of point A from sea level - Distance of point B from sea level
= 5700 - (​-39600)
= 45300 m

#### Page No 71:

Initial temperature of Srinagar at 6 p.m. = 1°C
Final temperature of Srinagar at midnight = −4°C
Change in temperature = Final temperature - Initial temperature
​= (−4 − 1)°C
= −5°C
So, the temperature has changed by −5°C.
So, the temperature has fallen by 5°C.

#### Page No 72:

(i) 15 by 9
= 15 × 9
= 135

(ii)
18 by −7
= –(18 × 7)
= –126

(iii) 29 by –11
= –(29 × 11)
= –319

(iv) –18 by 13

= –(18 × 13)
= –234

(v) –56 by 16
= –(56 × 16)
= –896

(vi) 32 by –21
= –(32 × 21)
= –672

(vii) –57 by 0

= –(57 × 0)
= 0

(viii) 0 by –31
= –(0 × 31)
= 0

(ix) –12 by –9
= (12) × ( 9)
= 108

(x) (–​746) by (–8)
= (746) × (8)
= 5968

(xi)
118 by −7
= 118 × (-7)
= –826

(xii) −238 by −143
= (238) × (143)
= 34034

#### Page No 73:

(i)  (–2) × 3 × (–4)
= [(–2) × 3] × (–4)
= (–6) × (–4)
= 24

(ii) 2 × (–5) × (–6)

= [2 × (–5)] × (–6)
= (–10) × (–6)
= 60

(iii) (–8) × 3 × 5

= [(–8) × 3] × 5
= (–24) × 5
= –120
(iv) 8 × 7 × (–10)
= [8 × 7] × (–10)
= 56 × (–10)
= –560
(v)  (–3) × (–7) × (–6)

= [(–3) × (–7)] × (–6)
= 21 × (–6)
= –126
(vi) (–8) × (–3) × (–9)
= [(–8) × (–3)] × (–9)
= 24 × (–9)
= –216

#### Page No 73:

(i) 18 × (–27) × 30
= (–27) × [18 × 30]
= (–27) × 540
= –14580

(ii) (–8) × (–63) × 9
= [(–8) × (–63)] × 9
= 504 × 9
= 4536

(iii) (–17) × (–23) × 41
= [(–17) × (–23)] × 41
= 391 × 41
= 16031

(iv) (–51) × (–47) × (–19)
= [(–51) × (–47)] × (–19)
= 2397 × (–19)
= – 45543

#### Page No 73:

(i)
L.H.S.
=18 × [9 + (–7)]
= 18 × [9 – 7]
= 18 × 2
= 36
R.H.S.
=18 × 9 + 18 × (–7)
= 162 – (18 × 7)
= 162 – 126
= 36

$\therefore$ L.H.S = R.H.S
Hence, verified.

(ii) (–13) × [(–6) + (–19)] = (–13) × (–6) + (–13) × (–19)
L.H.S.
= (–13) × [(–6) + (–19)]
= (–13) × [–6 – 19]
= (–13) × (–25)
= 325
R.H.S.
= (–13) × (–6) + (–13) × (–19)
= 78 + 247
= 325

$\therefore$ L.H.S = R.H.S
Hence, verified.

#### Page No 73:

 × –3 –2 –1 0 1 2 3 –3 9 6 3 0 –3 –6 –9 –2 6 4 2 0 –2 –4 –6 –1 3 2 1 0 –1 –2 –3 0 0 0 0 0 0 0 0 1 –3 –2 –1 0 1 2 3 2 –6 –4 –2 0 2 4 6 3 –9 –6 –3 0 3 6 9

#### Page No 73:

(i) The product of a positive integer and a negative integer is negative.
True

(ii) The product of two negative integers is a negative integer.
False
The product of two negative integers is always a positive integer.

(iii) The product of three negative integers is a negative integer.
True

(iv) Every integer when multiplied by (–1) gives its multiplicative inverse.
False

Every integer when multiplied by (1) gives its multiplicative inverse
.

#### Page No 73:

(i) (–9) × 6 + (–9) × 4
Solution:
Using the distributive law:
(–9) × 6 + (–9) × 4
= (–9) × (6+9)
= (–9) × 10
= –90

(ii) 8 × (–12) + 7 × (–12)
Solution:
Using the distributive law:
8 × (–12) + 7 × (–12)
= (–12) × (8+7)
= (–12) × 15
= –180

(iii) 30 × (–22) + 30 × (14)
Solution:
Using the distributive law:
30 × (–22) + 30 × (14)
= 30 × [(–22) + 14]
= 30 × [–22 + 14]
= 30 × (–8)
= –240

(iv) (–15) × (–14) + (–15) × (–6)
Solution:
(–15) × (–14) + (–15) × (–6)
Using the distributive law:
= (–15) × [ (–14) + (–6)]
= (–15) × [–14 – 6]
= (–15) × (–20)
= 300

(v) 43 × (–33) + 43 × (–17)
Solution:
43 × (–33) + 43 × (–17)
Using the distributive law:
= (43 ) × [–(33) + (–17)]
= (43 ) × [–33 – 17]
= 43 × (–50)
= –2150

(vi)  (–36) × (72) + (–36) × 28
Solution
(–36) × (72) + (–36) × 28
Using the distributive law:
= (–36) × (72 + 28 )
= (–36) × 100
= –3600

(vii) (–27) × (–16) + (–27) × (–14)
Solution:
(–27) × (–16) + (–27) × (–14)
Using the distributive law:
= (–27) × [(–16) + (–14)]
= (–27) × [–16 –14]
= (–27) × [–30]
= 810

#### Page No 75:

(i) 85 by 17

$\frac{-85}{17}$
= –5

(ii) –72 by 18

=$\frac{-72}{18}$
= –4
(iii) –80 by 16

$\frac{-80}{16}$
= –5

(iv) –121 by 11

=$\frac{-121}{11}$
= –11

(v) 108 by –12

=  $\frac{108}{-12}$
= –9
(vi)  –161 by 23

$\frac{-161}{23}$
= –7

(vii) –76 by –19

=$\frac{-76}{-19}$
= 4

(viii) –147 by –21

$\frac{-147}{-21}$
= 7
(ix) –639 by –71

$\begin{array}{l}=\frac{-639}{-71}\\ =9\end{array}$
(x) –639 by –71

$\begin{array}{l}=\frac{-639}{-71}\\ =9\end{array}$
(x) –15625 by –125

$\begin{array}{l}=\frac{-15625}{-125}\\ =125\end{array}$

(xi) 2067 by –1

$\begin{array}{l}=\frac{2067}{-1}\\ =-2067\end{array}$

(xii) 1765 by –1765

(xiii) 0 by –278

$\begin{array}{l}=\frac{0}{-278}\\ =0\end{array}$

(xiv) 3000 by –100

$\begin{array}{l}=\frac{3000}{-100}\\ =-30\end{array}$

#### Page No 75:

(i) 80 ÷ (–16) = –5
(ii) (–84) ÷ (12) = –7
(iii) (–125) ÷ (–5) = 25
(iv) (0) ÷ (372) = 0
(v) (–186) ÷ 1 = –186
(vi) (–34) ÷ 17 = –2
(vii) (–165) ÷ 165 = –1
(viii) (–73) ÷ –1 = 73
(ix) 1 ÷ (–1) = –1

#### Page No 75:

(i) True
(ii) False
This is because we cannot divide any integer by 0. If we do so, we get the quotient as infinity.
(iii) True
(iv) False
This is because the division of any two negative integers always gives a positive quotient.
(v) True
(vi) True
(vii) True
(viii) True
(ix) False
This is because the division of any two negative integers always gives a positive quotient.

#### Page No 75:

(b) –4 < –3
Since 4 is greater than 3, –4 is less than –3.

#### Page No 75:

(c) –5

2 less than –3 means the following:
= –3 – 2
= –5

#### Page No 76:

c) –1

4 more than –5 means the following:
= –5 + 4
= –1

#### Page No 76:

(a) –9

2 less than −7 means the following:
= −7 − 2
= −9

#### Page No 76:

(b) 10
7 + |-3|
= 7 + (+ 3)   (The absolute value of
−3 is 3.)
= 7 + 3
= 10

(c) –77
(−42) + (−35)
= −42 − 35
= −77

(b) –31
(
−37) + 6
=
−37 + 6
= −31

(c) 22
49 + (−27)
= 49 − 27
​= 22

#### Page No 76:

(c) –17

In succession, we move from the left to the right of the number line.

#### Page No 76:

(b) –17
To find the predecessor of a number, we move from the right to the left of a number line.

#### Page No 76:

(a) 5
If we add the additive inverse of a number to the number, we get 0.

−5 + 5 = 0

(b) –7
−12 − (−5)
= −12 + 5
= −7

(b) 13.5 − (−8)
= 5 + 8
= 13

#### Page No 76:

(c) –55
Let x be the other integer.
x + 30 = –25
$⇒$ x = 2530
$⇒$ x = 55

#### Page No 76:

(a) 25

Let the other integer be x
x + (-5) = 20

$⇒$x - 5 = 20
$⇒$x = 25

#### Page No 76:

(b) 21

Let the other integer be x.
x + 8 = 13
=> x  = 13 8
=> x = 21

(b) 8

0
(8)
= 0 + 8
= 8

(c) 0

8 + (
8
= 8

= 0

(c) 1

(−6) + 4 − (−3)
= −6 + 4 + 3
= −6 + 7
= 1

(c) 10
6 − (−4)
= 6 + 4
= 10

#### Page No 76:

(a) –20
(−7) + (−9) + 12 + (−16)
= −7 − 9 + 12 −16
= −20

(c) –12
–​4 –​ 8
= –​12

(c) 3

We have:

−6 − (−9)
= −6 + 9
= 3

(c) 15

We have:

10  − (−5)
​= 10 + 5
= 15

(b) –54
We have:

(−6) × 9
= −(6 × 9​)
= −54

#### Page No 77:

(a) –90

(−9) × 6 + (−9) × 4
Using distributive law:
(−9) × (6 + 4)
= (−9) × (10)
= −90

(b) –4

36 ÷ (−9)

#### Page No 78:

The numbers ...–4, –3, –2, –1, 0, 1, 2, 3, 4... are integers.
The group of positive and negative numbers including 0 is called integers.

–5, –4, –3, –2, –1, 0, 1, 2, 3, 4, 5

#### Page No 78:

(i) 0, –3
0
This is because 0 is greater than any negative integer.

(ii) –4, –6
–4
Since 6 is greater than 4, –4 is greater than –6
.

(iii) –99, 9
9
This is because every positive integer is greater than any negative integer.

(iv) –385, –615
–385
Since 615 is greater than 385, –385 is greater than –615.

#### Page No 78:

We can arrange the given integers in the increasing order in the following manner:
–36, –18, –5, –1, 0, 1, 8, 16

(i) 9 – |–6|
= 9 – (6)
= 9
– 6

= 3

(ii) 6 + |–4|

= 6 + (4)
= 6 + 4

= 10

(iii) –8 – |–3|
= –8 – 3
= –11

#### Page No 78:

Four integers less than –6 (i.e. four negative integers that lie to the left of –6) are –7, –8, –9 and –10.
Four integers greater than –6 (i.e. four negative integers that lie to the right of –6 ) are –5, –4, –3 and –2.

#### Page No 78:

(i) 8 + (–16)
= 8 – 16
= –8

(ii) (–5) + (–6)
= –5 – 6
= –11

(iii) (–6) × (–8)
= (6 × 8)
= 48

(iv) (–36) ÷ 6

(v)
30 – (–50)
= 30 + 50
= 80

(vi) (–40) ÷ (–10)
$\begin{array}{l}=\frac{-40}{-10}\\ =\frac{\left(-1\right)×40}{\left(-1\right)×10}\\ =4\end{array}$

(vii) 8 × (–5)
= –(8 × 5)
= –40

(viii) (–30) – 15
= –30 – 15
= –45

#### Page No 78:

Let the integer be x.
$\therefore$ 34 + x = –12
or x = –12 – 34
or x = –46
Therefore, the other integer is –46.

#### Page No 78:

(i) (–24) × (68) + (–24) × 32
= –(24) × (68+32)
= –24 × 100
= –2400

(ii) (–9) × 18 – (–9) × 8
= –(9 ) × [18 – 8]
= –9 × 10
= –90

(iii) (–147) ÷ (–21)

$\begin{array}{l}=\frac{-147}{-21}\\ =\frac{\left(-1\right)×147}{\left(-1\right)×21}\\ =\frac{\left(-1\right)}{\left(-1\right)}×\frac{147}{21}\\ =7\end{array}$

(iv) 16 ÷ (–1)

$\begin{array}{l}=\frac{16}{-1}\\ =\frac{16×\left(-1\right)}{\left(-1\right)×\left(-1\right)}\\ =16×\left(-1\right)\\ =-16\end{array}$   {Multiplying the numerator and the denominator by (–1)}

#### Page No 78:

(b) −88
The successor of −89 is ​−88. The successor of a number lies towards its right on a number line. ​
−88 lies to the right of ​−89.

#### Page No 78:

(b) ​−100
The predecessor of a number lies to the left of the number.
​​−100 lies to the left of −​99. Hence, ​​−100 is a predecessor of −​99.

#### Page No 78:

(c) ​23
23 + 23 = 0
Hence, 23 is the additive inverse of  −23.

#### Page No 78:

(b) >

Here, L.H.S. = (13 + 6
=
−7

R.H.S. =
25  (9)
=
25 + 9
​            =
−16

−7 > −16

L.H.S. > R.H.S.

(c) 20

x + (−8) = 12
=> x − 8 = 12
=> x = 12 + 8
=> x = 20

#### Page No 78:

(c) -2

5 more than (−7) means 5 added to (−7).
5 + (7)
= 5 7
= 2

#### Page No 78:

(d) −47
Let the number to be added to 16 be x.
x + 16 = (−31)
=> x = (−31)−16
=> x = −47

(d) −70
−36 ​− 34
= −70

#### Page No 78:

(i)
Let the required number be x.
23 x = 15
=> 23 = 15 + x
=> 15 + x = 23
=> x = 15 23
=> x = 38

(ii)
The largest negative integer is -1.

(iii)
The smallest positive integer is 1.

(iv)
(−8) + (−6) − (−3)
= (−8) + (−6) +3
= −8 ​−6 + 3
= 11

(v)
The predecessor of −200:
(−200 − 1)
= −201

#### Page No 79:

(i) T
(ii) F

−(−36) − 1
= 36
− 1​
= 35

(iii) F
This is because −10 is less than −6.

(iv) T

(v) T

−|−15|
= ​−(15)
= −15

​(vi) F

|−40| + 40
= 40 + 40
= 80

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